SCUT Training 20170920 Problem O
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原题:http://codeforces.com/contest/589/problem/I
思路:
水题,把每种编号缺少数量加起来就行
源代码:
#include<cstdio> #include<string>#include <cstring>using namespace std;int a[110];int main(){ int n,m,mm,i,j,k; while(scanf("%d%d",&n,&m)!=EOF) { memset(a,0,sizeof(a)); mm=n/m; for(i=1;i<=n;i++) { scanf("%d",&k); a[k]++; } int sum=0; for(i=1;i<=m;i++) { if(a[i]<mm) { sum+=mm-a[i]; } } printf("%d\n",sum); } return 0;}
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- SCUT Training 20170920 Problem O
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- SCUT Training 20170920 Problem A
- SCUT Training 20170920 Problem B
- SCUT Training 20170920 Problem C
- SCUT Training 20170920 Problem D
- SCUT Training 20170920 Problem E
- SCUT Training 20170920 Problem F
- SCUT Training 20170920 Problem G
- SCUT Training 20170920 Problem H
- SCUT Training 20170920 Problem I
- SCUT Training 20170920 Problem J
- SCUT Training 20170920 Problem K
- SCUT Training 20170920 Problem L
- SCUT Training 20170920 Problem M
- SCUT Training 20170920 Problem N
- SCUT Training 20170920 Problem P
- SCUT Training 20170913 Problem A
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