231. Power of Two
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判断一个数是不是2的指数,需要首先排除掉负数
class Solution { public boolean isPowerOfTwo(int n) { if (n < 0) { return false; } int count = 0; for (int i = 0; i < 32; i++){ count += (n >>> i) & 1; } return count == 1 ? true : false; }}
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- 231. Power of Two
- 231. Power of Two
- 231. Power of Two
- 231. Power of Two
- 231. Power of Two
- 231. Power of Two
- 231. Power of Two
- 231. Power of Two
- 231. Power of Two
- 231. Power of Two
- 231. Power of Two
- 231. Power of Two
- 231. Power of Two
- 231. Power of Two
- 231. Power of Two
- 231. Power of Two
- 231. Power of Two
- 231. Power of Two
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