leetcode#7-Reverse Integer-java

题目：

Reverse digits of an integer.Example1: x = 123, return 321Example2: x = -123, return -321click to show spoilers.Note:The input is assumed to be a 32-bit signed integer. Your function should return 0 when the reversed integer overflows.

解法：

int start = 0;if(x<0){    start = 1;}char [] test = String.valueOf(x).toCharArray();int exp = 0;int result = 0;for(int i=start;i<test.length;i++){    result+=(test[i]-'0')*(Math.pow(10,exp));    exp++;}if(result>=Math.pow(2,31)-1){    return 0;}if(start==1){    result = result-result*2;}return result;