九度OJ题目1001：A+B for Matrices

题目描述：

    This time, you are supposed to find A+B where A and B are two matrices, and then count the number of zero rows and columns.

输入：

    The input consists of several test cases, each starts with a pair of positive integers M and N (≤10) which are the number of rows and columns of the matrices, respectively. Then 2*M lines follow, each contains N integers in [-100, 100], separated by a space. The first M lines correspond to the elements of A and the second M lines to that of B.

    The input is terminated by a zero M and that case must NOT be processed.

输出：

    For each test case you should output in one line the total number of zero rows and columns of A+B.

样例输入：

2 21 11 1-1 -110 92 31 2 34 5 6-1 -2 -3-4 -5 -60

样例输出：

15

来源：

2011年浙江大学计算机及软件工程研究生机试真题

答疑：

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#include <cstdio>const int maxn=12;int a[maxn][maxn],b[maxn][maxn],c[maxn][maxn];int main(){    int m,n;    while(~scanf("%d%d",&m,&n)&&m){        for(int i=0;i<m;i++)            for(int j=0;j<n;j++)                scanf("%d",&a[i][j]);        for(int i=0;i<m;i++)            for(int j=0;j<n;j++)                scanf("%d",&b[i][j]);        for(int i=0;i<m;i++)            for(int j=0;j<n;j++)                c[i][j]=a[i][j]+b[i][j];        int cnt=0;        for(int i=0;i<m;i++){            int ok=1;            for(int j=0;j<n;j++) if(c[i][j]) ok=0;            if(ok) cnt++;        }        for(int j=0;j<n;j++){            int ok=1;            for(int i=0;i<m;i++) if(c[i][j]) ok=0;            if(ok) cnt++;        }        printf("%d\n",cnt);    }    return 0;}