1002. A+B for Polynomials (25)
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1002. A+B for Polynomials (25)
时间限制
400 ms
内存限制
65536 kB
代码长度限制
16000 B
判题程序
Standard
作者
CHEN, Yue
This time, you are supposed to find A+B where A and B are two polynomials.
Input
Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 aN1 N2 aN2 ... NK aNK, where K is the number of nonzero terms in the polynomial, Ni and aNi (i=1, 2, ..., K) are the exponents and coefficients, respectively. It is given that 1 <= K <= 10,0 <= NK < ... < N2 < N1 <=1000.
Output
For each test case you should output the sum of A and B in one line, with the same format as the input. Notice that there must be NO extra space at the end of each line. Please be accurate to 1 decimal place.
Sample Input2 1 2.4 0 3.22 2 1.5 1 0.5Sample Output
3 2 1.5 1 2.9 0 3.2
题解:此题数据量很小,因此直接暴力,先存下第一个多项式,然后再利用map思想将第二项加上第一项得到答案,最后遍历输出答案。#include<stdio.h>double a[1100];int main(){ int k1,k2,e; double x; scanf("%d",&k1); for(int i=0; i<k1; i++) { scanf("%d %lf",&e,&x); a[e]=x; } scanf("%d",&k2); for(int i=0; i<k2; i++) { scanf("%d %lf",&e,&x); a[e]+=x; } int js=0; for(int i=1000; i>=0; i--) { if(a[i]) { js++; } } printf("%d",js); for(int i=1000; i>=0; i--) { if(a[i]) { printf(" %d %.1f",i,a[i]); } } printf("\n"); return 0;}
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