Python实现排序算法

来源:互联网 发布:vue.js 实现网页下载 编辑:程序博客网 时间:2024/05/22 12:20

快速排序

def quick_sort(lists, left, right):    if left >= right:        return lists    key = lists[left]    low = left    high = right    while left < right:        while left < right and lists[right] >= key:            right -= 1        lists[left] = lists[right]        while left < right and lists[left] <= key:            left += 1        lists[right] = lists[left]    lists[right] = key    quick_sort(lists, low, left - 1)    quick_sort(lists, left + 1, high)    return lists

插入排序

def insert_sort(lists):    count = len(lists)    for i in range(1, count):        key = lists[i]        j = i - 1        while j >= 0:            if lists[j] > key:                lists[j + 1] = lists[j]                lists[j] = key            j -= 1    return lists

归并排序

def merge(left, right):    i, j = 0, 0    result = []    while i < len(left) and j < len(right):        if left[i] <= right[j]:            result.append(left[i])            i += 1        else:            result.append(right[j])            j += 1    result += left[i:]    result += right[j:]    return resultdef merge_sort(lists):    if len(lists) <= 1:        return lists    num = len(lists) / 2    left = merge_sort(lists[:num])    right = merge_sort(lists[num:])    return merge(left, right)

希尔排序

def shell_sort(lists):    count = len(lists)    step = 2    group = count / step    while group > 0:        for i in range(0, group):            j = i + group            while j < count:                k = j - group                key = lists[j]                while k >= 0:                    if lists[k] > key:                        lists[k + group] = lists[k]                        lists[k] = key                    k -= group                j += group        group /= step    return lists
原创粉丝点击