single-number-ii
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题目:
Given an array of integers, every element appears three times except for one. Find that single one.
Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?
程序:
class Solution {public: int singleNumber(int A[], int n) { int one = 0, two = 0, three = 0; for(int i = 0; i < n; i++) { two |= one & A[i]; one ^= A[i]; three = ~(one & two); one &= three; two &= three; } return one; }};
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