HDU 1061 Rightmost Digit

Rightmost Digit

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 58454    Accepted Submission(s): 22145

Problem Description

Given a positive integer N, you should output the most right digit of N^N.

 

Input

The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.
Each test case contains a single positive integer N(1<=N<=1,000,000,000).

 

Output

For each test case, you should output the rightmost digit of N^N.

 

Sample Input

234

 

Sample Output

76
Hint
In the first case, 3 * 3 * 3 = 27, so the rightmost digit is 7.In the second case, 4 * 4 * 4 * 4 = 256, so the rightmost digit is 6.
 

 

题目大意：给你一个n，求出n^n的最后一位数字

快速幂入门题

#include<iostream>using namespace std;typedef long long ll;ll qui(ll n){ll ans=1;ll base=n;while(n){if(n&1) ans=ans*base%10;base=base*base%10;n>>=1;}return ans;}int main(){int t;cin>>t;while(t--){ll n;cin>>n;cout<<qui(n)<<endl;}}