leetcode.array--40. Combination Sum II
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问题:40. Combination Sum II
问题描述:https://leetcode.com/problems/combination-sum-ii/description/
题目意思是说,从一个给定的序列中找出相加等于target的组合,要求每一个元素只能使用一次,这个以前用C写过不少啦,DFS如下:
Python:
class Solution(object): def combinationSum2(self, candidates, target): """ :type candidates: List[int] :type target: int :rtype: List[List[int]] """ vis=[] for i in range(len(candidates)): vis.append(0) def dfs(nums,target,path,res): if target<0: return if target==0 and path not in res: return res.append(path) for i in range(len(nums)): if vis[i]!=0 or target<nums[i]: return else: vis[i]=1 dfs(nums,target-nums[i],path+[nums[i]],res) vis[i]=0 res=[] dfs(sorted(candidates),target,[],res) return res
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