mysql | 计算排名

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> 计算排名

    •  计算排名
    • 给出每个人的排名
    • LeetCode上的计算排名
      • 方案一
      • 方案二
      • 方案三
      • 方案四

例子:
https://www.1keydata.com/tw/sql/sql-rank.html

给出每个人的排名

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SELECT a1.Name, a1.Sales, COUNT(a2.Sales) Sales_Rank FROM Total_Sales a1, Total_Sales a2 WHERE a1.Sales <= a2.Sales OR (a1.Sales=a2.Sales AND a1.Name = a2.Name) GROUP BY a1.Name, a1.Sales ORDER BY a1.Sales DESC, a1.Name DESC;

LeetCode上的计算排名:

https://leetcode.com/problems/rank-scores/description/
这里写图片描述

结果:
这里写图片描述

方案一:

SELECT  Score,  @rank := @rank + (@prev <> (@prev := Score)) RankFROM  Scores,  (SELECT @rank := 0, @prev := -1) initORDER BY Score desc

方案二:

SELECT  Score,  (SELECT count(distinct Score) FROM Scores WHERE Score >= s.Score) RankFROM Scores sORDER BY Score desc

方案三:

SELECT  Score,  (SELECT count(*) FROM (SELECT distinct Score s FROM Scores) tmp WHERE s >= Score) RankFROM ScoresORDER BY Score desc

方案四:

SELECT s.Score, count(distinct t.score) RankFROM Scores s JOIN Scores t ON s.Score <= t.scoreGROUP BY s.IdORDER BY s.Score desc

总结出来,以供自己学习之用。

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