sum of all integer numbers
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sum of all integer numbers
时间限制:1000 ms | 内存限制:65535 KB
难度:0
- 描述
- Your task is to find the sum of all integer numbers lying between 1 and N inclusive.
- 输入
- There are multiple test cases.
The input consists of a single integer N that is not greater than 10000 by it's absolute value. - 输出
- Write a single integer number that is the sum of all integer numbers lying between 1 and N inclusive.
- 样例输入
3
- 样例输出
6
代码实现:(注意要区分n大于0和小于0的情况)
#include<stdio.h>
int main()
{
int n;
long i,sum;
while(scanf("%d",&n)!=EOF)
{
sum=0;
if(n>0)
{
for(i=1;i<=n;i++)
sum+=i;
}
else
{
for(i=1;i>=n;i--)
sum+=i;
}
printf("%d\n",sum);
}
return 0;
}
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