HDOJ 2088 Box of Bricks

HDACM2088
此题只要先求出平均值，然后把低于平均值的个数求出来，并且求和，最后再把average*个数-sum就能得出需要移动的个数，
注意：每两行之间要有一个空行

import java.util.Scanner;public class Main{    public static void main(String[] args) {        Scanner sc = new Scanner(System.in);        boolean isFirst = true;        while(sc.hasNext()){            int n = sc.nextInt();            if (n==0) {                break;            }            if (isFirst) {                isFirst = false;            }else {                System.out.println();            }            int[] m = new int[n];            int sum = 0;            for (int i = 0; i < m.length; i++) {                m[i] = sc.nextInt();                sum += m[i];            }            int average = sum/n;            sum = 0;            int k = 0;            for (int i = 0; i < m.length; i++) {                if (m[i]<average) {                    sum += m[i];                    k++;                }            }            System.out.println(average*k-sum);        }    }}