写一个函数，检测输入的数字旋转180度后是否相等，比如619旋转后还是619.

用递归的方法很容易实现：

#coding=utf-8def turnover(n):    if len(n) == 0:        return True    elif len(n) == 1:        return n in '018'    elif (n[0]==n[-1] and n[0] in '018') \         or n[0]+n[-1] in '969':        return turnover(n[1:-1])    else:        return Falsetest_cases = """0 1 6 8 9 10 11 18 69 80 88 91 96 99 100 101 111 121  619 916 6699 18181 """for test_num in test_cases.split():    print(test_num, turnover(test_num))

Python 3.6.2 (v3.6.2:5fd33b5, Jul  8 2017, 04:57:36) [MSC v.1900 64 bit (AMD64)] on win32
Type "copyright", "credits" or "license()" for more information.
>>> 
============================ RESTART: F:\tmp\1.py ============================
0 True
1 True
6 False
8 True
9 False
10 False
11 True
18 False
69 True
80 False
88 True
91 False
96 True
99 False
100 False
101 True
111 True
121 False
619 True
916 True
6699 True
18181 True
>>>