HDU 2192 MagicBuilding

http://acm.hdu.edu.cn/showproblem.php?pid=2192

 

MagicBuilding

TimeLimit: 1000/1000 MS(Java/Others)    MemoryLimit: 32768/32768 K (Java/Others)
Total Submission(s):576    AcceptedSubmission(s): 253

Problem Description

As the increase of population, theliving space for people is becoming smaller and smaller. InMagicStar the problem is much worse. Dr. Mathematica is trying tosave land by clustering buildings and then we call the set ofbuildings MagicBuilding. Now we can treat the buildings as a squareof size d, and the height doesn't matter. Buildings ofd1,d2,d3....dn can be clustered into one MagicBuilding if theysatisfy di != dj(i != j).
Given a series of buildings size , you need to calculate theminimal numbers of MagicBuildings that can be made. Note that onebuilding can also be considered as a MagicBuilding.
Suppose there are five buildings : 1, 2, 2, 3, 3. We make threeMagicBuildings (1,3), (2,3), (2) .And we can also make twoMagicBuilding :(1,2,3), (2,3). There is at least two MagicBuildingsobviously.

 

Input

The first line of the input is a singlenumber t, indicating the number of test cases.
Each test case starts by n (1≤n≤10^4) in a line indicating thenumber of buildings. Next n positive numbers (less than 2^31) willbe the size of the buildings.

 

Output

For each test case , output a numberperline, meaning the minimal number of the MagicBuilding that canbe made.

 

Sample Input

2 1 2 5 1 22 3 3

 

Sample Output

1 2

 

Author

scnu

 

Recommend

lcy

 

题意：给出一组数据，找出其中相同数字出现次数的最大值。

分析：感觉是一道简单题，我用哈希做得，一直是running time error实在是找不出问题。请帮忙看看，到底是哪里出错了。

代码如下：

#include<iostream>
#include<algorithm>
#include<string.h>
using namespace std;
int haxi[10050];
int main()
{
   int T,n,w,k,max,i;
  scanf("%d",&T);
   while(T--)
   {
   scanf("%d",&n);
   memset(haxi,0,sizeof(haxi));
    max=0;
   while(n--)
    {
    scanf("%d",&w);
    haxi[w]++;
  if(max<w)max=w;   
    }
   max=max+1;
    sort(haxi,haxi+max);
   printf("%d\n",haxi[max-1]);
   }
   return0; 
}

 

最后只能换一种方法，哈希是用不了了。网上找到一个

http://hi.baidu.com/���ƻ���/blog/item/e5df48ee973fabdab31cb1ad.html

（其实我感觉使用哈希应该比他的巧妙一点点。。。^-^）

代码如下：

#include<iostream>
#include <algorithm>
using namespace std;

int main()
{
   int t;
   int n, i;
   int a[10001];
   scanf("%d",&t);
   while (t--){
       scanf("%d",&n);
       for (i = 0; i<n;++i){
           scanf("%d",&a[i]);
       }
       sort(a, a+n);
   int len = 1;
   for (i = 1; i<n;++i){
       if (a[i]== a[i-len]) len++;
   }
   printf("%d\n", len);
   }
   return 0;
}