A

Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input
The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output
Print single integer: the number of columns the table should have.

Example
Input
1 7
Output
6
Input
1 1
Output
5
Input
11 6
Output
5
Note
The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.】

#include<iostream>using namespace std;int a[13] = { 0,31,28,31,30,31,30,31,31,30,31,30,31 };int main(){    int m, n;    while (cin >> m >> n)    {        int ans = a[m];        if (((ans + n - 7-1) % 7) != 0)            ans= (ans + n - 7 - 1) /7+2;        else            ans= (ans + n - 7 - 1) /7+1;        cout << ans << endl;    }    return 0;}