编程找出1000以内的完数，并按下面格式输出因子：6 its factors are 1 2 3

void is_Perfectnumber(int number) //判断完数并输出{    int i = 0;    int j = 0;    int sum = 0;    int arr[100] = { 0 };//定义一个数组，存储因子    for (i = 1; i <= number/2; i++) //判断完数    {        if (0 == number % i)        {            arr[j] = i;            j++;            sum = sum + i;        }    }    if (number == sum)    {        printf("%3d its factors are ",sum);        int k = 0;        for (k = 0; k < j; k++)  //输出完数的各个因子        {            printf("%d ", arr[k]);        }        printf("\n");    }}int main(){    int num = 0;    for (num = 1; num <= 1000; num++)    {        is_Perfectnumber(num);    }    system("pause");    return 0;}