实验C—5 任意十进制数转化为二进制

设计思路：

十进制转二进制无非相除取余，然后余数倒序输出，即为先进后出，应该使用栈。

代码：

#include<iostream>using namespace std;class Translate {int data;Translate *next, *top;public:Translate() { top = NULL; }void push(int);void pop();};void Translate::push(int x) {Translate *p = new Translate;p->data = x; p->next = top; top = p;}void Translate::pop() {Translate *p = new Translate;while (top){p = top;cout << top->data;top = top->next;delete p;}}void main() {int n; Translate p;cout << "输入十进制数：" << endl; cin >> n;while (n != 0){p.push(n % 2);n /= 2;}cout << endl;cout << "二进制数为：";p.pop();cout << endl;}

实验测试图：