用Lock和Condition，实现主线程执行5次，子线程再执行10次，孙线程执行15次，如此反复5次

package test1;import java.util.concurrent.locks.Condition;import java.util.concurrent.locks.Lock;import java.util.concurrent.locks.ReentrantLock;/** * 用Lock和Condition，实现主线程执行5次，子线程再执行10次，孙线程执行15次，如此反复5次 *  * 设计思想： * 业务类Business中，设计3个方法，每个方法代表主、子、孙 * 主方法中执行5次 * 子方法中执行10次 * 孙方法中执行15次 *  * 用lock锁住各自方法，然后用runFlag来判断是否自己执行，如果不是，则await，如果走完，则把runFlag设为下一个要执行的对象 * 然后用condition来唤醒下一线程 * */public class CommunicationTest3 {public static void main(String[] args) {final Business2 business = new Business2();new Thread(new Runnable() {@Overridepublic void run() {for (int i = 0; i < 5; i++) {business.sub2(i);}}}){}.start();new Thread(new Runnable() {@Overridepublic void run() {for (int i = 0; i < 5; i++) {business.sub3(i);}}}){}.start();for (int i = 0; i < 5; i++) {business.sub(i);}}}class Business2 {private int runFlag = 1;private Lock lock = new ReentrantLock();Condition c1 = lock.newCondition();Condition c2 = lock.newCondition();Condition c3 = lock.newCondition();public void sub(int i) {lock.lock();try {if (runFlag != 1) {try {c1.await(); // 如果不是sub1执行时，让出CPU} catch (Exception e) {e.printStackTrace();}}for (int j = 0; j < 5; j++) {System.out.println("sub1-" + i + "下的" + j + "次");}runFlag = 2; // 执行完后，让sub执行c2.signal();} finally {lock.unlock();}}public void sub2(int i) {lock.lock();try {if (runFlag != 2) {try {c2.await(); // 如果不是sub2该执行时，让出CPU} catch (Exception e) {e.printStackTrace();}}for (int j = 0; j < 10; j++) {System.out.println("sub2-" + i + "下的" + j + "次");}runFlag = 3; // 执行完后，让sub执行c3.signal();} finally {lock.unlock();}}public void sub3(int i) {lock.lock();try {if (runFlag != 3) {try {c3.await(); // 如果不是sub3该执行时，让出CPU} catch (Exception e) {e.printStackTrace();}}for (int j = 0; j < 15; j++) {System.out.println("sub3-" + i + "下的" + j + "次");}runFlag = 1; // 执行完后，让sub1执行c1.signal();} finally {lock.unlock();}}}