leetcode.array--64. Minimum Path Sum
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题目:64. Minimum Path Sum
题目链接:https://leetcode.com/problems/minimum-path-sum/description/
给定一个非负整数的二维矩阵,起点在左上方终点在右下方,找到从起点到终点的一条路径,使得通过该路径的花费最小,返回该路径上所有数字的和。
同样是一个dp,设dp[i][j]为到达grid[i-1][j-1]的最小开销,则有dp[i][j]=grid[i-1][j-1]+min(dp[i][j-1],dp[i-1][j])。
Python:
class Solution(object): def minPathSum(self, grid): """ :type grid: List[List[int]] :rtype: int """ rows=len(grid) columns=len(grid[0]) inf=0x7fffffff dp=[[inf for col in range(columns+1)] for row in range(rows+1)] dp[1][1]=grid[0][0] for i in range(1,rows+1): for j in range(1,columns+1): if i==1 and j==1: continue dp[i][j]=grid[i-1][j-1]+min(dp[i][j-1],dp[i-1][j]) return dp[rows][columns]
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