基于java的enigma的加密程序

import java.util.*;
public class enigma {
 static public void main(String[] arg){
  String P;
  String M;//明文
  int key1,key2,key3 = 0;
        Scanner in=new Scanner(System.in); //使用Scanner类定义对象
        System.out.println("请输入明文：");
        P=in.nextLine();
        System.out.println("请输入密钥" +"\n"+"请输入第一个密码轮的初始位置：");
       key1=in.nextInt();
       System.out.println("请输入第二个密码轮的初始位置：");
       key2=in.nextInt();
       System.out.println("请输入第三个密码轮的初始位置：");
       key3=in.nextInt();
       P=P.toUpperCase();// 将明文转换成大写
       P=P.replaceAll("[^A-Z]", "");//去除所有非字母的字符    
       Encrypt en = new Encrypt();
       Decrypt  dec=new Decrypt();
       M=en.encrypt(key1, key2, key3, P);
       dec.decrypt(key1, key2, key3, M);
 }
 
}
class Encrypt{
 String encrypt(int key1,int key2,int key3,String str){
  String m="";
  char[] chara={'A','B','C','D','E','F','G','H','I','J'};
  int[] list={1,2,3,4,5,6,7,8,9,10};
  int[] firstCycle={3,8,7,5,2,9,1,10,6,4};
  int[] secondCycle={8,6,2,5,4,7,3,9,1,10};
  int[] thirdCycle={4,7,8,2,3,1,10,6,5,9};
  int counter1=10,counter2=10,counter3=10,i,j,k1,k2,k3;
  for(i=0;i<str.length();i++){
   for(j=0;j<10;j++){
    if(str.charAt(i)==chara[j])
     break;
   }
   if((counter1+j-key1)<0)
    j=10+j+counter1-key1;
   else
    j=j+counter1-key1;
   for(k1=0;k1<10;k1++){
    if(list[(j)%10]==firstCycle[k1])
     break;
   }
   k1=10-counter1+k1;
   if((counter2+k1-key2)<0)
    k1=10+counter2+k1-key2;
   else
    k1=counter2+k1-key2;
   for(k2=0;k2<10;k2++){
    if(list[(k1)%10]==secondCycle[k2])
     break;
   }
   k2=10-counter2+k2;
   if((counter3+k2-key3)<0)
    k2=10+counter3+k2-key3;
   else
    k2=counter3+k2-key3;
   for(k3=0;k3<10;k3++){
    if(list[(k2)%10]==thirdCycle[k3]){
     break;
    }
   }
   m+=chara[(k3+key3+10-counter3)%10];
   counter3--;
   if(counter3==0)
   {
    counter3=10;
    counter2--;
    if(counter2==0){
     counter2=10;
     counter1--;
     if(counter1==0)
      counter1=10;
     
    }
    
   }
   
  }
  System.out.println("密文是："+m);
  return m;
  
  
 }
 
}
class Decrypt{
 void decrypt(int key1,int key2,int key3,String str){
  String m="";
  char[] chara={'A','B','C','D','E','F','G','H','I','J'};
  int[] list={1,2,3,4,5,6,7,8,9,10};
  int[] firstCycle={3,8,7,5,2,9,1,10,6,4};
  int[] secondCycle={8,6,2,5,4,7,3,9,1,10};
  int[] thirdCycle={4,7,8,2,3,1,10,6,5,9};
  int counter1=10,counter2=10,counter3=10,i,j,k1,k2,k3;
  for(i=0;i<str.length();i++){
   for(j=0;j<10;j++){
    if(str.charAt(i)==chara[j])
     break;
   }
   if((counter3+j-key3)<0)
    j=10+j+counter3-key3;
   else
    j=j+counter3-key3;
   for(k1=0;k1<10;k1++){
    if(thirdCycle[(j)%10]==list[k1])
     break;
   }
   k1=10-counter3+k1;
   k1=counter2+k1+key3;
   for(k2=0;k2<10;k2++){
    if(secondCycle[(k1)%10]==list[k2])
     break;
   }
   k2=10-counter2+k2;
   k2=counter1+k2+key2;
   for(k3=0;k3<10;k3++){
    if(firstCycle[(k2)%10]==list[k3]){
     break;
    }
   }
   m+=chara[(k3+key1+10-counter1)%10];
   counter3--;
   if(counter3==0)
   {
    counter3=10;
    counter2--;
    if(counter2==0){
     counter2=10;
     counter1--;
     if(counter1==0)
      counter1=10;
     
    }
    
   }
   
  }
  System.out.println("明文是："+m);
 }
 
}