计蒜客ACM ICPC 2017 Warmup Contest 9--I题-Sticky Situation

• 2000ms
•  65536K

While on summer camp, you are playing a game of hide-and-seek in the forest. You need to designate a “safe zone”, where, if the players manage to sneak there without being detected,they beat the seeker. It is therefore of utmost importance that this zone is well-chosen.

You point towards a tree as a suggestion, but your fellow hide-and-seekers are not satisfied. After all, the tree has branches stretching far and wide, and it will be difficult to determine whether a player has reached the safe zone. They want a very specific demarcation for the safe zone. So, you tell them to go and find some sticks, of which you will use three to mark anon-degenerate triangle (i.e. with strictly positive area) next to the tree which will count as the safe zone. After a while they return with a variety of sticks, but you are unsure whether you can actually form a triangle with the available sticks.

Can you write a program that determines whether you can make a triangle with exactly three of the collected sticks?

Input

The first line contains a single integer N , with 3 ≤ N ≤ 20 000, the number of sticks collected. Then follows one line with Npositive integers, each less than 2^{60}2​60​​, the lengths of the sticks which your fellow campers have collected.

Output

Output a single line containing a single word: possible if you can make a non-degenerate triangle with three sticks of the provided lengths, and impossible if you can not. 

样例输入1

31 1 1

样例输出1

possible

样例输入2

53 1 10 5 15

样例输出2

impossible

#include<iostream>#include<algorithm>using namespace std;int n;long long a[20001];long long sum;int main(){while(scanf("%d",&n)!=EOF){for(int i=0;i<n;i++) scanf("%lld",&a[i]);sort(a,a+n);bool flag=false;for(int i=0;i<n-2;i++){sum=a[i]+a[i+1];if(sum<=a[i+2]) continue;if(sum>a[i+2]){flag=true;break;}}if(flag) printf("possible\n");else printf("impossible\n");}return 0;}