CodeForces344B
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Mad scientist Mike is busy carrying out experiments in chemistry. Today he will attempt to join three atoms into one molecule.
A molecule consists of atoms, with some pairs of atoms connected by atomic bonds. Each atom has a valence number — the number of bonds the atom must form with other atoms. An atom can form one or multiple bonds with any other atom, but it cannot form a bond with itself. The number of bonds of an atom in the molecule must be equal to its valence number.
Mike knows valence numbers of the three atoms. Find a molecule that can be built from these atoms according to the stated rules, or determine that it is impossible.
Input
The single line of the input contains three space-separated integers a, b and c (1 ≤ a, b, c ≤ 106) — the valence numbers of the given atoms.
Output
If such a molecule can be built, print three space-separated integers — the number of bonds between the 1-st and the 2-nd, the 2-nd and the 3-rd, the 3-rd and the 1-st atoms, correspondingly. If there are multiple solutions, output any of them. If there is no solution, print “Impossible” (without the quotes).
Example
Input
1 1 2
Output
0 1 1
Input
3 4 5
Output
1 3 2
Input
4 1 1
Output
Impossible
import org.omg.PortableInterceptor.SYSTEM_EXCEPTION;import java.util.Arrays;import java.util.Scanner;/** * Created by 95112 on 10/22/2017. */public class Molecule { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); int[] atoms = new int[3]; int[] storageAtoms = new int[3]; int[] answer = new int[3]; for (int i =0 ; i< 3 ; i++) { atoms[i] = scanner.nextInt(); storageAtoms[i] = atoms[i]; } Arrays.sort(atoms); if (atoms[0] <= 0 ) { System.out.println("Impossible"); return; } if (atoms[2] > atoms[1]+atoms[0]){ System.out.println("Impossible"); return; } int dValue = atoms[1] - atoms[0]; if ((atoms[2] - dValue)%2 == 1) { System.out.println("Impossible"); return; } else { int tmpDValue = storageAtoms[1] - storageAtoms[2]; if (tmpDValue < 0 ){ answer[0] =( storageAtoms[0] + tmpDValue)/2; answer[2] = answer[0] - tmpDValue; answer[1] = storageAtoms[1] - answer[0]; } else { answer[0] = (storageAtoms[0] - tmpDValue)/2 + tmpDValue; answer[2] = (storageAtoms[0] - tmpDValue)/2; answer[1] = storageAtoms[1] - answer[0]; } } for (int ans : answer) System.out.print(ans+" "); }}