python--选择排序

每一趟从元素列表中选取一个最小的元素作为有序序列中第i个元素｡

@param: A: an integer array@return: """def sortIntegers(self, A):    # write your code here    for i  in range(0,len(A)):        min = A[i]        min_index =i        for j in range(i+1,len(A)):            if A[j]<min:                min = A[j]                min_index = j        A[min_index]=A[i]        A[i]=min    return A