1132. Cut Integer (20)

题目：

Cutting an integer means to cut a K digits long integer Z into two integers of (K/2) digits long integers A and B. For example, after cutting Z = 167334, we have A = 167 and B = 334. It is interesting to see that Z can be devided by the product of A and B, as 167334 / (167 x 334) = 3. Given an integer Z, you are supposed to test if it is such an integer.

Input Specification:

Each input file contains one test case. For each case, the first line gives a positive integer N (<= 20). Then N lines follow, each gives an integer Z (10<=Z<=231). It is guaranteed that the number of digits of Z is an even number.

Output Specification:

For each case, print a single line “Yes” if it is such a number, or “No” if not.

Sample Input:
3
167334
2333
12345678
Sample Output:
Yes
No
No

解答：

//A1132#include<cstdio>#include<cmath>int main(){    int n,num;    scanf("%d",&n);    for(int i=0;i<n;i++){        scanf("%d",&num);        int len=0,temp=num;        while(temp){            temp/=10;            len++;        }        int p=pow(10,len/2);        int a=num/p;        int b=num%p;        if(a*b!=0&&num%(a*b)==0)printf("Yes\n");        else printf("No\n");    }    return 0;}