HDU

来源:互联网 发布:滴定度的浓度算法 编辑:程序博客网 时间:2024/06/05 08:17

为了得到更多的那个东西,需要 J [ i ] / F [ i ] 的值尽量大

定义结构体排序就好了,,



#include <iostream>#include <cstdio>#include <string>#include <cstring>#include <algorithm>#include <cmath>#include <queue>#include <vector>#include <set>#include <stack>#include <map>#include <climits>using namespace std;typedef long long ll;const int maxn = 100000, INF = 0x3f3f3f3f;int n, m;struct node {    double v, w;    double ans;}a[maxn];bool cmp(node a, node b) {    return a.ans > b.ans;}int main() {    while(~scanf("%d %d", &n, &m)) {        if(n == -1 && m == -1) break;        for(int i = 0; i < m; ++i) {            //cin >> a[i].v >> a[i].w;            scanf("%lf%lf", &a[i].v, &a[i].w);            a[i].ans = a[i].v / a[i].w;        }        sort(a, a+m, cmp);        double ans = 0;        for(int i = 0; i < m; ++i) {            if(n <= 0) break;            //ans += (a[i].ans * min(n, (int)a[i].w) );            if(n >= a[i].w) {                ans += a[i].v;            } else ans += (a[i].ans * n);            n -= a[i].w;        }        //cout << ans << endl;        printf("%.3lf\n", ans);    }    return 0;}


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