HDU
来源:互联网 发布:滴定度的浓度算法 编辑:程序博客网 时间:2024/06/05 08:17
为了得到更多的那个东西,需要 J [ i ] / F [ i ] 的值尽量大
定义结构体排序就好了,,
#include <iostream>#include <cstdio>#include <string>#include <cstring>#include <algorithm>#include <cmath>#include <queue>#include <vector>#include <set>#include <stack>#include <map>#include <climits>using namespace std;typedef long long ll;const int maxn = 100000, INF = 0x3f3f3f3f;int n, m;struct node { double v, w; double ans;}a[maxn];bool cmp(node a, node b) { return a.ans > b.ans;}int main() { while(~scanf("%d %d", &n, &m)) { if(n == -1 && m == -1) break; for(int i = 0; i < m; ++i) { //cin >> a[i].v >> a[i].w; scanf("%lf%lf", &a[i].v, &a[i].w); a[i].ans = a[i].v / a[i].w; } sort(a, a+m, cmp); double ans = 0; for(int i = 0; i < m; ++i) { if(n <= 0) break; //ans += (a[i].ans * min(n, (int)a[i].w) ); if(n >= a[i].w) { ans += a[i].v; } else ans += (a[i].ans * n); n -= a[i].w; } //cout << ans << endl; printf("%.3lf\n", ans); } return 0;}