将‘循环输入’,放到循环之初 与 循环之尾 的区别
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循环体:输入-判断-重复或结束
1.导致多输入一次才结束: 放到循环之初 :
public static void find_top_5_8() { Scanner input=new Scanner(System.in); int num=0,score=0,max=0,count=0; String name="",name_max=""; System.out.println("Enter how many students: "); num=input.nextInt(); //先在外部输入第一次的输入值: System.out.println("Enter the name and it's score: "); name=input.next(); score=input.nextInt(); while (count < num) { if (max < score) { max=score; name_max=name; } count++; //在循环的尾部,输入下一个输入值 name=input.next(); score=input.nextInt(); //显化:每次的输入后,循环体内的变化 System.out.println("The top name,score,and count is: "+name_max+" "+max+" "+count); } System.out.println("The top score student is: "+name_max); }产生的结果:
Enter how many students: 3Enter the name and it's score: a 11b 22The top name,score,and count is: a 11 1c 33 此时,又进入循环体,count++后又要求一次输入,才结束循环,外输入后,循环体: 判断-输入-重复或结束The top name,score,and count is: b 22 2d 44 要多输入一对值,才能运行完The top name,score,and count is: c 33 3The top score student is: c
2.正确方法: 放在在循环之初,且不在外部先输入值:
public static void find_top_5_8() { Scanner input=new Scanner(System.in); int num=0,score=0,max=0,count=0; String name="",name_max=""; System.out.println("Enter how many students: "); num=input.nextInt(); while (count < num) { 在每次循环初始,输入值,才能满足 循环体:输入-判断-重复或结束 System.out.println("Enter the name and it's score: "); name=input.next(); score=input.nextInt(); if (max < score) { max=score; name_max=name; } count++; //显化:每次的输入后,循环体内的变化 System.out.println("The top name,score,and count is: "+name_max+" "+max+" "+count); } System.out.println("The top score student is: "+name_max); }
运行结果:
Enter how many students: 3Enter the name and it's score: a 11The top name,score,and count is: a 11 1Enter the name and it's score: b 22The top name,score,and count is: b 22 2Enter the name and it's score: c 33The top name,score,and count is: c 33 3The top score student is: c
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