Codeforces Educational Codeforces Round 31

A. Book Reading

time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

Recently Luba bought a very interesting book. She knows that it will take t seconds to read the book. Luba wants to finish reading as fast as she can.

But she has some work to do in each of n next days. The number of seconds that Luba has to spend working during i-th day is ai. If some free time remains, she can spend it on reading.

Help Luba to determine the minimum number of day when she finishes reading.

It is guaranteed that the answer doesn't exceed n.

Remember that there are 86400 seconds in a day.

Input

The first line contains two integers n and t (1 ≤ n ≤ 100, 1 ≤ t ≤ 106) — the number of days and the time required to read the book.

The second line contains n integers ai (0 ≤ ai ≤ 86400) — the time Luba has to spend on her work during i-th day.

Output

Print the minimum day Luba can finish reading the book.

It is guaranteed that answer doesn't exceed n.

Examples

input

2 286400 86398

output

2

input

2 864000 86400

output

1

题意：Luba 想花 t 秒来读书，但是每天Luba要花ai秒来工作，ta只能在没有工作时看书，问多少天能看 t 秒的书，天数不会超过n

#include<iostream>#include<string.h>#include<stdio.h>using namespace std;#define LL long longint main(){    int n,t,a,ans = 0;    scanf("%d%d",&n,&t);    for(int i=1;i<=n;i++){        scanf("%d",&a);        t -= (86400-a);        if(t<=0&&ans==0) ans = i;    }    cout<<ans<<endl;;    return 0;}