1-bit and 2-bit Characters问题及解法

问题描述：

We have two special characters. The first character can be represented by one bit 0. The second character can be represented by two bits (10 or 11).

Now given a string represented by several bits. Return whether the last character must be a one-bit character or not. The given string will always end with a zero.

示例:

Input: bits = [1, 0, 0]Output: TrueExplanation: The only way to decode it is two-bit character and one-bit character. So the last character is one-bit character.

Input: bits = [1, 1, 1, 0]Output: FalseExplanation: The only way to decode it is two-bit character and two-bit character. So the last character is NOT one-bit character.

问题分析：

每次记录最后出现的字符是否为只有0构成的，最终返回记录标识即可。

过程详见代码：

class Solution {public:    bool isOneBitCharacter(vector<int>& bits) {        bool res = 0;for (int i = 0; i < bits.size();){if (!bits[i]){i++;res = 1;}else{i += 2;res = 0;}}return res;    }};