Java中计算时间差的方法

假设现在是2004-03-26 13：31：40
过去是：2004-01-02 11：30：24
要获得两个日期差，差的形式为：XX天XX小时XX分XX秒
方法一：

DateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");try{  Date d1 = df.parse("2004-03-26 13:31:40");  Date d2 = df.parse("2004-01-02 11:30:24");  long diff = d1.getTime() - d2.getTime();  long days = diff / (1000 * 60 * 60 * 24);}catch (Exception e){}

方法二：

SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");java.util.Date now = df.parse("2004-03-26 13:31:40");java.util.Date date=df.parse("2004-01-02 11:30:24");long l=now.getTime()-date.getTime();long day=l/(24*60*60*1000);long hour=(l/(60*60*1000)-day*24);long min=((l/(60*1000))-day*24*60-hour*60);long s=(l/1000-day*24*60*60-hour*60*60-min*60);System.out.println(""+day+"天"+hour+"小时"+min+"分"+s+"秒");

方法三：

SimpleDateFormat dfs = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");java.util.Date begin=dfs.parse("2004-01-02 11:30:24");java.util.Date end = dfs.parse("2004-03-26 13:31:40");long between=(end.getTime()-begin.getTime())/1000;//除以1000是为了转换成秒long day1=between/(24*3600);long hour1=between%(24*3600)/3600;long minute1=between%3600/60;long second1=between%60/60;System.out.println(""+day1+"天"+hour1+"小时"+minute1+"分"+second1+"秒");