leetcode 165
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我的代码效率居然排100%
但看别人的代码我这个代码不够精简。
var search1 = function ( version1 ,version2) { pos1 = version1.indexOf('.'); pos2 = version2.indexOf('.'); if(pos1==-1 && pos2==-1){ if(parseFloat(version1)==parseFloat(version2)){ return 0; }else{ return parseFloat(version1)>parseFloat(version2)?1:-1; } } if (pos1 != -1) { n11 = parseFloat(version1.substr(0, pos1)); n12 = version1.substr(pos1 + 1, version1.length - pos1 - 1); } else { n11 = parseFloat(version1); n12 = "0"; } if (pos2 != -1) { n21 = parseFloat(version2.substr(0, pos2)); n22 = version2.substr(pos2 + 1, version2.length - pos2 - 1); } else { n21 = parseFloat(version2); n22 = "0"; } //console.log(n11,n21,n12,n22); if (n11 != n21) { return n11 > n21 ? 1 : -1; } return search1(n12,n22);};return search1(version1,version2);
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