2.A+B——the first step
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1000 1001
A + B Problem
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 704421 Accepted Submission(s): 217867
Problem Description
Calculate A + B.
Input
Each line will contain two integers A and B. Process to end of file.
Output
For each case, output A + B in one line.
Sample Input
1 1
Sample Output
2
Author
HDOJ
#include<iostream> #include<cmath>#include<cstring>#include<string>#include<algorithm>#include<iomanip>#include<cstdio>using namespace std;int main(){ /*ios::sync_with_stdio(false); cin.tie(0);理论上,scanf 和 printf 要比cin 和 cout 快,但是加上这两行之后就会使cin cout比 scanf printf 都要快。但是用了“ ios::sync_with_stdio(false); cin.tie(0); “ 之后,scanf 和 printf 都不能使用了,只能使用cin 和 cout。 详见http://blog.csdn.net/jinzhilong580231/article/details/7697608 http://www.cnblogs.com/bofengyu/p/6720041.html 等其他相关操作*/ int a,b,sum=0; while(cin>>a>>b) { sum=a+b; cout<<sum<<endl; } return 0; }
Sum Problem
Time Limit: 1000/500 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 502828 Accepted Submission(s): 127638
Problem Description
Hey, welcome to HDOJ(Hangzhou Dianzi University Online Judge).
In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.
In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.
Input
The input will consist of a series of integers n, one integer per line.
Output
For each case, output SUM(n) in one line, followed by a blank line. You may assume the result will be in the range of 32-bit signed integer.
Sample Input
1100
Sample Output
15050
Author
DOOM III
#include <iostream>using namespace std;int main(){ long long n; while( cin>>n ) { cout<<( n*(n+1) ) / 2<<endl<<endl; } return 0;}
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