Leetcode: 300. Longest Increasing Subsequence
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c++ code：
class Solution {public: int lengthOfLIS(vector<int>& nums) { vector<int> dp(nums.size(), 1); int ans = 0; for (int i = 0; i < nums.size(); ++i) { for (int j = 0; j < i; ++j) { if (nums[i] > nums[j]) { dp[i] = max(dp[i], dp[j] + 1); } } ans = max(ans, dp[i]); } return ans; }};算法：
采用动态规划，维护一个dp数组， dp[i]代表以第i个数结尾的最长递增子序列，初始化为一，之后对每一个 i 检查其前面所有元素，从而更新dp数组。 最终得到的最大dp[?] 即为所求结果。 此算法时间复杂度为O(n^2).
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