大数阶乘

import java.math.BigInteger;import java.util.Scanner;public class Bigshu {public static void main(String[] rags) {Scanner sc=new Scanner(System.in);int n;n=sc.nextInt();//BigInteger BigInt=new BigInteger("1");BigInteger BigInt=BigInteger.ONE;for(int i=1;i<=n;i++) {String str=String.valueOf(i);BigInt=BigInt.multiply(new BigInteger(str));}System.out.print(BigInt);}}

#include <stdio.h>#include <string.h>const int maxn = 3000;int f[maxn];int main() {int i, j, n;scanf("%d", &n);memset(f, 0, sizeof(f));f[0] = 1;for(i = 2; i <= n; i++) { /* 乘以i */int c = 0;for(j = 0; j < maxn; j++) {int s = f[j] * i + c;f[j] = s % 10;c = s / 10;}}for(j = maxn-1; j >= 0; j--)        if(f[j])             break; for(i = j; i >= 0; i--)         printf("%d", f[i]);printf("\n");return 0;}