UVa 10370 Above Average
来源:互联网 发布:大数据神经网络 编辑:程序博客网 时间:2024/06/05 07:46
输出百分比时直接乘以100然后相除即可
#include<stdio.h>int main(void){ int T, n, score[1005], count, percent; double ave, sum; scanf("%d", &T); while (T--) { sum = ave = 0.0; count = 0; scanf("%d", &n); for (int i = 0; i < n; i++) { scanf("%d", &score[i]); sum += (double)score[i]; } ave = sum / n; for (int i = 0; i < n; i++) { if ((double)score[i] > ave) { count++; } } printf("%.3f%%\n", (count * 100.0) / n); } return 0;}
阅读全文
0 0
- UVA 10370 - Above Average
- UVa 10370 - Above Average
- UVa 10370 Above Average
- UVa 10370 Above Average (water ver.)
- 10370 - Above Average
- Above Average
- Above Average
- Above Average
- Above Average
- Above Average
- fjnu 1518 Above Average
- FZU 1629 Above Average
- zoj 1915 Above Average
- poj 2350 Above Average
- zoj1915--------------------Above Average
- ZOJ 1915 Above Average
- HOJ 1962 Above Average
- ZOJ 1915 Above Average
- 回文算法
- Thrift 客户端 C# ---实现zookeeper监视(1)
- 大数据预科19(补充之线程)
- C#简单的在图片上添加文字并保存
- 再谈找负环
- UVa 10370 Above Average
- ACM准备之路(蓝桥杯5)杨辉三角公式解法
- 浅谈DMA
- Mybatis源码(三)之SqlSession执行流程全貌
- JAVA项目中数据库表的设计思路
- 第三个春天
- 操作系统实验——内存管理
- L1-030. 一帮一
- C语言基础(一)