C和指针之判断参数在关键字字符串列表中是否匹配

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1、题目

*判断参数是否与一个关键字列表任何单词匹配
*并返回匹配的索引值，如果没有找到返回-1

2、代码实现

#include <stdio.h>#include <stdlib.h>#include <string.h>/** *判断参数是否与一个关键字列表任何单词匹配 *并返回匹配的索引值，如果没有找到返回-1 **/int lookup_keyword(const char *const desired,const char *keyword[], int const size){    const char **p;    for (p = keyword; p < keyword + size; p++)    {        if (strcmp(desired, *p) == 0)        {           return p - keyword;        }    }    return -1;}int main(){    const char *keyword[] = {"chen", "gong", "yu", "cai"};    const char *const desired = "yu";    int size = sizeof(keyword) / sizeof(keyword[0]);    printf("size is %d\n", size);    int result = lookup_keyword(desired, keyword, size);    printf("result is %d\n", result);    return 0;}

3、运行结果

1111deMacBook-Pro:dabian a1111$ vim lookup_keyword.c1111deMacBook-Pro:dabian a1111$ gcc -g lookup_keyword.c -o lookup_keyword1111deMacBook-Pro:dabian a1111$ ./lookup_keywordsize is 4result is 2

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