A+B for Input-Output Practice (II) java

来源:互联网 发布:php单例模式 编辑:程序博客网 时间:2024/06/06 02:50

其实吧,这第二道题感觉也不是我写的啦,在第一道题的时候,百度了,看到有相关的,然后算是抄袭吧,哈哈哈,这第二道题是第一道题的进化版,循序渐进的题,还不错。他们写的也很不错。

题目详情:Your task is to Calculate a + b.
Input:Input contains an integer N in the first line, and then N lines follow. Each line consists of a pair of integers a and b, separated by a space, one pair of integers per line.

Output:For each pair of input integers a and b you should output the sum of a and b in one line, and with one line of output for each line in input.

Sample Input:
2
1 5
10 20

Sample Output:
6
30

代码如下:

import java.util.Scanner;  public class Main {      public static void main(String[] args) {          Scanner sc = new Scanner(System.in);        int n = sc.nextInt();        while(n-->0){              int a = sc.nextInt();              int b = sc.nextInt();              System.out.println(a+b);          }      }  }  

其实while和for应该是相通的,可以试试for循环,这是我在写这篇文章的时候写的

代码如下:

import java.util.Scanner;  public class Main {      public static void main(String[] args) {          Scanner sc = new Scanner(System.in);        int n = sc.nextInt();   for(int i=0;i<n;i++){              int a = sc.nextInt();              int b = sc.nextInt();              System.out.println(a+b);          }      }  }  

不过是第一段代码的时间比较短,空间也是第一段好。