python print UUID的问题

在项目中遇到了使用uuid作为主键的情况，有时为了测试方便会加几个print在代码里面，后来在一段代码中前后print内容一致的情况下，if 判定不等的条件一直为True，后来想到了之前也遇到了uuid转换为str使用的情况，这是解决问题的一个办法。

这里要说的是print函数打印的问题，如果遇到特殊类型最好带上类型，下面是python官方文档对print的解释：

print(*objects, sep=’ ‘, end=’\n’, file=sys.stdout, flush=False)Print objects to the text stream file, separated by sep and followed by end. sep, end, file and flush, if present, must be given as keyword arguments.**All non-keyword arguments are converted to strings like str() does and written to the stream, separated by sep and followed by end.** Both sep and end must be strings; they can also be None, which means to use the default values. If no objects are given, print() will just write end.

下面做了一个实验是用print和sys.stdout.write打印的对比：

In [34]: for i in a:    ...:     sys.stdout.write(i)    ...:     ---------------------------------------------------------------------------TypeError                                 Traceback (most recent call last)<ipython-input-34-a7af1453478a> in <module>()      1 for i in a:----> 2     sys.stdout.write(i)      3 TypeError: write() argument must be str, not UUID

标准输出是不接受UUID的。

In [28]: a = [uuid.uuid4() for n in range(1, 5)]In [29]: aOut[29]: [UUID('6015667f-7f50-4b85-baee-694aa1f93ee6'), UUID('5d5da498-2f55-46e3-bd0f-73ae574fc686'), UUID('651f06f3-4680-4d1d-a7ce-223799bfa12b'), UUID('1ccc9386-97f1-4a2a-ac1d-5bd112b498f1')]In [30]: print(a)[UUID('6015667f-7f50-4b85-baee-694aa1f93ee6'), UUID('5d5da498-2f55-46e3-bd0f-73ae574fc686'), UUID('651f06f3-4680-4d1d-a7ce-223799bfa12b'), UUID('1ccc9386-97f1-4a2a-ac1d-5bd112b498f1')]In [31]: for i in a:    ...:     print(i)    ...:     6015667f-7f50-4b85-baee-694aa1f93ee65d5da498-2f55-46e3-bd0f-73ae574fc686651f06f3-4680-4d1d-a7ce-223799bfa12b1ccc9386-97f1-4a2a-ac1d-5bd112b498f1

单独打印一个UUID的列表是会带上标记的，但是如果单独打印其中一个的话就会出现print解释中的str转换再打印的情况。