python根据函数进行列表排序

l = [1,-8,7,-2,0]


l1 = [(abs(x),x) for x in l]  #abs（）只能有一个参数
print l1
l1.sort()


ranked=[v for (s,v) in l1]

print ranked

输出：

[(1, 1), (8, -8), (7, 7), (2, -2), (0, 0)]
[0, 1, -2, 7, -8]