数组例题

#include<stdio.h>#define RESPONSES_SIZE 40#define FREQUENCY_SIZE 11int main() {    int frequency[FREQUENCY_SIZE] = { 0 };    int responses[RESPONSES_SIZE] = { 1,2,6,4,8,5,9,7,8,10,1,6,3,8,6,10,3,8,2,7,6,5,7,6,8,6,7,5,6,6,5,6,7,5,6,4,8,6,8,10 };    //answer增加，responses[i]就会改变，frequency[p](p=responses[i])就会改变了（计数）    for (int answer = 0; answer < RESPONSES_SIZE; ++answer) {        ++frequency[responses[answer]];    }    printf("%s%17s\n", "Rating", "Frequency");//打印表头    for (int rating = 1; rating < FREQUENCY_SIZE; ++rating) {        printf("%6d%17d\n", rating, frequency[rating]);    }    return 0;}

之所以frequency定义成拥有11个元素，是因为出现分数1时，对frequency[1]而非frequency[0]增值。这样可以直接将分数当成下标来访问数组frequency中的元素。（忽略元素0）（书p167）