python中处理嵌套的字典的函数

适用场景

# 假设我们有: Val = {'a': {'b': {'c': 1}}}

常规方案:

Val.get('a', {}).get('b', {}).get('c', None)

试试 dget吧

def dget(dictionary, cmd, default=None):    cmd_list = cmd.split('.')    tmp = dict(dictionary)    for c in cmd_list:        try:            val = tmp.get(c, None)        except AttributeError:            return default        if val!= None:            tmp = val        else:            return default    return tmpif __name__ == "__main__":    data = {'a':{'b':{'c':1}}}    dget(data, 'a.b.c') # 1    dget(data, 'a.d.e') # None    dget(data, 'a.b') # {'c': 1}