判断两个时间区间是否存在交集-Java实现

以下demo用于判断两个时间区间是否存在交集.

代码如下:

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package com.tgy.demo;


import java.text.SimpleDateFormat;
import java.util.*;


public class DateCrossDemo {
/**
* 判断两个时间区间是否有交集的方法
* 
* @param date1_1
*            区间1的时间始
* @param date1_2
*            区间1的时间止
* @param date2_1
*            区间2的时间始
* @param date2_2
*            区间2的时间止
* @return 区间1和区间2如果存在交集,则返回true,否则返回falses
*/
public static boolean isDateCross(Date date1_1, Date date1_2, Date date2_1, Date date2_2) {
boolean flag = false;// 默认无交集
long l1_1 = date1_1.getTime();
long l1_2 = date1_2.getTime();
long l2_1 = date2_1.getTime();
long l2_2 = date2_2.getTime();

if((l1_1>l1_2)||(l2_1>l2_2))

throw new Exception("Parameter error:date1_1 should not be great than date1_2 and date2_1 should not be great than date2_2");
if (((l1_1 <= l2_1) && (l2_1 <= l1_2)) || ((l1_1 <= l2_2) && (l2_2 <= l1_2))
|| ((l2_1 <= l1_1) && (l1_1 <= l2_2)) || ((l2_1 <= l1_2) && (l1_2 <= l2_2))) {
flag = true;
}
return flag;
}


public static void main(String[] args) throws Exception {
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd");
String dateStr1_1 = "2017-10-01";
String dateStr1_2 = "2017-10-03";
String dateStr2_1 = "2017-10-02";
String dateStr2_2 = "2017-10-04";
Date date1_1 = sdf.parse(dateStr1_1);
Date date1_2 = sdf.parse(dateStr1_2);
Date date2_1 = sdf.parse(dateStr2_1);
Date date2_2 = sdf.parse(dateStr2_2);
boolean b = isDateCross(date1_1, date1_2, date2_1, date2_2);
System.out.println(b == true ? "有交集" : "无交集");
}
}