HDOJ1002 A + B Problem II

A + B Problem II

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 387443    Accepted Submission(s): 75000

Problem Description

I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.

 

Input

The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.

 

Output

For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.

 

Sample Input

21 2112233445566778899 998877665544332211

 

Sample Output

Case 1:1 + 2 = 3Case 2:112233445566778899 + 998877665544332211 = 1111111111111111110

 

使用java的BigInteger相当简单，加起来输出就OK了

import java.math.BigInteger;import java.util.Scanner;public class Main{private static Scanner scanner;public static void main(String[] args) {scanner = new Scanner(System.in);int cases = scanner.nextInt();for (int i = 1; i <= cases; i++) {String aString = scanner.next();String bString = scanner.next();BigInteger aInteger = new BigInteger(aString);BigInteger bInteger = new BigInteger(bString);BigInteger sumInteger = new BigInteger(""+aInteger.add(bInteger));if(i>1){System.out.println();}System.out.println("Case "+i+":");System.out.println(aString+" + "+bString+" = "+sumInteger);}}}