uva 401（回文词）

https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&category=829&problem=342&mosmsg=Submission+received+with+ID+20398535

#include<iostream>#include<string>#include<string.h>using namespace std;string r="A   3  HIL JM O   2TUVWXY501SE Z  8 ";char *m_c="AHIMOTUVWXY018";char mir_c(char c){    if(c>='A'&&c<='Z')    {        c=r[c-'A'];    }    else if(c>='0'&&c<='9')//如果不是else if 那么变成2的S又会变回S        c=r[c-'0'+26];    return c;}int  main(){    string s;    while(cin>>s)    {    int n=s.size();    int m1=2,m2=3,i;//先判断对称，再判断镜像    for(i=0;i<n/2;i++)    {        if(s[i]!=s[n-i-1]) m1=1;        if(mir_c(s[i])!=s[n-i-1])        {            //cout<<mir_c(s[i])<<" "<<s[n-i-1];            m2=1;        }    }    if((n%2==1)&&strchr(m_c,s[n/2])==NULL) m2=1;//判断中间一位是不是镜像的    //cout<<m1<<" "<<m2<<" ";    cout<<s;    switch(m1*=m2)    {        case 1:cout<<" -- is not a palindrome."<<endl<<endl;break;        case 2:cout<<" -- is a regular palindrome."<<endl<<endl;break;        case 3:cout<<" -- is a mirrored string."<<endl<<endl;break;        case 6:cout<<" -- is a mirrored palindrome."<<endl<<endl;break;    }    }    return 0;}