[LeetCode] 27.Remove Element

• 题目描述
• 解题思路
• 实验代码

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题目描述

Given an array and a value, remove all instances of that value in-place and return the new length.

Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.

The order of elements can be changed. It doesn’t matter what you leave beyond the new length.

Example:

Given nums = [3,2,2,3], val = 3,

Your function should return length = 2, with the first two elements of nums being 2.

解题思路

这道题比较容易理解和解决，就是在一个vector中的所有数中将给定的数给去除掉，然后把后面的元素挪到前面，具体解决方法见代码，比较简单。

实验代码

class Solution {public:    int removeElement(vector<int>& nums, int val) {        int t = 0, s = nums.size();        for (int i = 0 ; i < s ; i++) {            if (nums[i] == val)                t++;            else nums[i-t] = nums[i];        }        return s - t;    }};