3.Tree Traversals (Inorder, Preorder and Postorder)[数据结构]

Inorder Traversal:

Algorithm Inorder(tree)
1. Traverse the left subtree, i.e., call Inorder(left-subtree)
2. Visit the root.
3. Traverse the right subtree, i.e., call Inorder(right-subtree)
Uses of Inorder
In case of binary search trees (BST), Inorder traversal gives nodes in non-decreasing order. To get nodes of BST in non-increasing order, a variation of Inorder traversal where Inorder itraversal s reversed, can be used.

Preorder Traversal:

Algorithm Preorder(tree)
1. Visit the root.
2. Traverse the left subtree, i.e., call Preorder(left-subtree)
3. Traverse the right subtree, i.e., call Preorder(right-subtree)
Uses of Preorder
Preorder traversal is used to create a copy of the tree. Preorder traversal is also used to get prefix expression on of an expression tree. Please see http://en.wikipedia.org/wiki/Polish_notation to know why prefix expressions are useful.

Postorder Traversal:

Algorithm Postorder(tree)
1. Traverse the left subtree, i.e., call Postorder(left-subtree)
2. Traverse the right subtree, i.e., call Postorder(right-subtree)
3. Visit the root.
Uses of Postorder
Postorder traversal is used to delete the tree. Please see the question for deletion of tree for details. Postorder traversal is also useful to get the postfix expression of an expression tree. Please see http://en.wikipedia.org/wiki/Reverse_Polish_notation to for the usage of postfix expression.

递归遍历

#include<stdio.h>#include<stdlib.h>struct node{    int data;    struct node* left;    struct node* right;};// allocates a new node with given datastruct node* newNode(int data){    struct node* node = (struct node*)malloc(sizeof(struct node));    node->data = data;    node->left = NULL;    node->right = NULL;    return(node);}// postordervoid printPostorder(struct node* node){    if(node == NULL)        return;    printPostorder(node->left);    printPostorder(node->right);    printf("%d ",node->data);}// inordervoid printInorder(struct node* node){    if(node == NULL)        return;    printInorder(node->left);    printf("%d ", node->data);    printInorder(node->right);}//preordervoid printPreorder(struct node* node){    if(node == NULL)        return;    printf("%d ", node->data);    printPreorder(node->left);    printPreorder(node->right);}int main(){    struct node* root = newNode(1);    root->left = newNode(2);    root->right           = newNode(3);     root->left->left     = newNode(4);     root->left->right   = newNode(5);      printf("\nPreorder traversal of binary tree is \n");     printPreorder(root);     printf("\nInorder traversal of binary tree is \n");     printInorder(root);       printf("\nPostorder traversal of binary tree is \n");     printPostorder(root);     getchar();     return 0;}

// Java program for different tree traversals/* Class containing left and right child of current   node and key value*/class Node{    int key;    Node left, right;    public Node(int item)    {        key = item;        left = right = null;    }}class BinaryTree{    // Root of Binary Tree    Node root;    BinaryTree()    {        root = null;    }    /* Given a binary tree, print its nodes according to the      "bottom-up" postorder traversal. */    void printPostorder(Node node)    {        if (node == null)            return;        // first recur on left subtree        printPostorder(node.left);        // then recur on right subtree        printPostorder(node.right);        // now deal with the node        System.out.print(node.key + " ");    }    /* Given a binary tree, print its nodes in inorder*/    void printInorder(Node node)    {        if (node == null)            return;        /* first recur on left child */        printInorder(node.left);        /* then print the data of node */        System.out.print(node.key + " ");        /* now recur on right child */        printInorder(node.right);    }    /* Given a binary tree, print its nodes in preorder*/    void printPreorder(Node node)    {        if (node == null)            return;        /* first print data of node */        System.out.print(node.key + " ");        /* then recur on left sutree */        printPreorder(node.left);        /* now recur on right subtree */        printPreorder(node.right);    }    // Wrappers over above recursive functions    void printPostorder()  {     printPostorder(root);  }    void printInorder()    {     printInorder(root);   }    void printPreorder()   {     printPreorder(root);  }    // Driver method    public static void main(String[] args)    {        BinaryTree tree = new BinaryTree();        tree.root = new Node(1);        tree.root.left = new Node(2);        tree.root.right = new Node(3);        tree.root.left.left = new Node(4);        tree.root.left.right = new Node(5);        System.out.println("Preorder traversal of binary tree is ");        tree.printPreorder();        System.out.println("\nInorder traversal of binary tree is ");        tree.printInorder();        System.out.println("\nPostorder traversal of binary tree is ");        tree.printPostorder();    }}

非递归遍历

class Node{    int key;    Node left,right;    Node(int val)    {        key = val;        left = right = null;    }}class BinaryTree{    Node root;    BinaryTree()    {        root = null;    }    void printPostorder(Node node)    {        if(node == null)        {            return;        }        printPostorder(node.left);        printPostorder(node.right);        System.out.print(node.key+" ");    }    void printPostorderNonRecursive(Node root)    {        Stack<Node> stack = new Stack<Node>();        Node currnode = root;        Node lastvisit = root;        while(!stack.isEmpty()||currnode!=null){            while(currnode!=null){                stack.push(currnode);                currnode = currnode.left;            }            currnode = stack.peek();            if(currnode.right==null||currnode.right==lastvisit){                System.out.print(currnode.key+" ");                stack.pop();                lastvisit = currnode;                currnode = null;            }else{                currnode = currnode.right;            }        }    }    /* Given a binary tree, print its nodes in inorder*/    void printInorder(Node node)    {        if (node == null)            return;        /* first recur on left child */        printInorder(node.left);        /* then print the data of node */        System.out.print(node.key + " ");        /* now recur on right child */        printInorder(node.right);    }    void printInorderNonRecursive(Node root)    {        Node node  = root;        Stack<Node> stack = new Stack<Node>();        while(node!=null||!stack.isEmpty())        {            while(node!=null){                stack.push(node);                node = node.left;            }            if(!stack.isEmpty())            {                node = stack.pop();                System.out.print(node.key+" ");                node = node.right;            }        }    }    /* Given a binary tree, print its nodes in preorder*/    void printPreorder(Node node)    {        if (node == null)            return;        /* first print data of node */        System.out.print(node.key + " ");        /* then recur on left sutree */        printPreorder(node.left);        /* now recur on right subtree */        printPreorder(node.right);    }    void printPreorderNonRecursive(Node root)    {        Stack<Node> stack = new Stack<Node>();        stack.push(root);        while(!stack.isEmpty()){            Node node = stack.pop();            if(node.right!=null){                stack.push(node.right);            }            if(node.left!=null){                stack.push(node.left);            }            System.out.print(node.key+" ");        }    }    // Wrappers over above recursive functions    void printPostorder()  {     printPostorder(root);  }    void printInorder()    {     printInorder(root);   }    void printPreorder()   {     printPreorder(root);  }    public static void main(String[] args){        BinaryTree tree =  new BinaryTree();        tree.root = new Node(1);        tree.root.left = new Node(2);        tree.root.right = new Node(3);        tree.root.left.left = new Node(4);        tree.root.left.right = new Node(5);        System.out.println("Preorder traversal of binary tree is ");        tree.printPreorder();        System.out.println("\nInorder traversal of binary tree is ");        tree.printInorder();        System.out.println("\nPostorder traversal of binary tree is ");        tree.printPostorder();    }}

http://www.geeksforgeeks.org/tree-traversals-inorder-preorder-and-postorder/