HDU 1570 A C（暴力）

A C

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 5686 Accepted Submission(s): 3697

Problem Description
Are you excited when you see the title “AC” ? If the answer is YES , AC it ;

You must learn these two combination formulas in the school . If you have forgotten it , see the picture.

Now I will give you n and m , and your task is to calculate the answer .

Input
In the first line , there is a integer T indicates the number of test cases.
Then T cases follows in the T lines.
Each case contains a character ‘A’ or ‘C’, two integers represent n and m. (1<=n,m<=10)

Output
For each case , if the character is ‘A’ , calculate A(m,n),and if the character is ‘C’ , calculate C(m,n).
And print the answer in a single line.

Sample Input2A 10 10C 4 2Sample Output36288006AuthorlinleSourceHDU 2007-1 Programming Contest

#include<iostream>#include<algorithm>#include<cstdio>#include<cstring>using namespace std;int main(){    int t;    scanf("%d",&t);    int n,m;    char a;    int as[11];    as[0]=1;    for(int i=1;i<=10;i++)        as[i]=as[i-1]*i;    while(t--)    {        getchar();        scanf("%c %d %d",&a,&n,&m);        if(a=='A')        {            printf("%d\n",as[n]/as[n-m]);        }        else        {            printf("%d\n",as[n]/(as[m]*as[n-m]));        }    }    return 0;}