PAT考试乙级1057(C语言实现)

#include<stdio.h> #include<string.h> #include<ctype.h> int main(){    int num,i,len,sum=0,c1=0,c2=0;    char a[10001];    gets(a);    len=strlen(a);    for(i=0;i<len;i++){        if('a'<=tolower(a[i])&&tolower(a[i])<='z'){//不要写成'a'<=tolower(a[i])<='z'            sum=sum+tolower(a[i])-'a'+1;        }    }    while(sum!=0){        if(sum%2==0) c1++;        else c2++;        sum=sum/2;    }    printf("%d %d",c1,c2);    return 0;}