两张yuv图片叠加

程序实现将一个400x400的yuv420p小图,覆盖在一张640x480的yuv420p大图上

#include <stdio.h>#include <stdint.h>#include <cstring>int main(int argc, char **argv){    int sw = 400, sh=400;    int bw = 640, bh = 480;    FILE* fp1 = NULL;    fopen_s(&fp1,"400x400.yuv","rb");    FILE* fp2 = NULL;    fopen_s(&fp2, "640x480.yuv", "rb");    char* yuv1 = new char[sw*sh*3/2];    char* yuv2 = new char[bw*bh*3/2];    fread(yuv1, sw * sh * 3/2,1,fp1);    fread(yuv2, bw * bh * 3/2, 1, fp2);    char* y1 = yuv1;    char* u1 = y1 + sw * sh;    char* v1 = u1 + sw * sh / 4;    char* y2 = yuv2;    char* u2 = y2 + bw*bh;    char* v2 = u2 + bw * bh / 4;    //从图像左上角开始进行yuv覆盖    for (int i = 0; i < sh; i++){ //每次循环一次，扫描一行数据        memcpy(y2, y1, sw); //y值覆盖        memcpy(u2, u1, sw / 2); //注意：根据采样比例，每一行的Y是每一行的U的两倍        memcpy(v2, v1, sw/2);        //换行，指针偏移到行首        y2 += bw;        u2 += bw/2;        v2 += bw/2;        y1 += sw;        u1 += sw / 2;        v1 += sw / 2;    }    FILE* fpout = NULL;    fopen_s(&fpout, "mux_out.yuv", "wb");    fwrite(yuv2, bw * bh * 3/2,1 ,fpout);    fclose(fpout);    fclose(fp1);    fclose(fp2);    delete[] yuv1;    delete[] yuv2;    return 0;}