HDOJ1335 Basically Speaking（进制转换）

Basically Speaking

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 3642    Accepted Submission(s): 1487

Problem Description

The Really Neato Calculator Company, Inc. has recently hired your team to help design their Super Neato Model I calculator. As a computer scientist you suggested to the company that it would be neato if this new calculator could convert among number bases. The company thought this was a stupendous idea and has asked your team to come up with the prototype program for doing base conversion. The project manager of the Super Neato Model I calculator has informed you that the calculator will have the following neato features:
It will have a 7-digit display.

Its buttons will include the capital letters A through F in addition to the digits 0 through 9.

It will support bases 2 through 16.

 

Input

The input for your prototype program will consist of one base conversion per line. There will be three numbers per line. The first number will be the number in the base you are converting from. The second number is the base you are converting from. The third number is the base you are converting to. There will be one or more blanks surrounding (on either side of) the numbers. There are several lines of input and your program should continue to read until the end of file is reached.

 

Output

The output will only be the converted number as it would appear on the display of the calculator. The number should be right justified in the 7-digit display. If the number is to large to appear on the display, then print "ERROR'' (without the quotes) right justified in the display.

 

Sample Input

1111000  2 101111000  2 162102101  3 102102101  3 15  12312  4  2     1A 15  21234567 10 16   ABCD 16 15

 

Sample Output

    120     78   1765    7CA  ERROR  11001 12D687   D071

 题意：将将n进制的num 转换为 m进制。

要是转换时候大于七位数，输出  ERROR。否则按题目要求的格式输出。

import java.util.Scanner;public class Main{private static Scanner scanner;public static void main(String[] args) {scanner = new Scanner(System.in);while(scanner.hasNext()){//将n进制的num 转换为 m进制String num = scanner.next();int n = scanner.nextInt();int m = scanner.nextInt();//if(num.equals("0")){//不需要//System.out.printf("%7d",0);//System.out.println();//}//先转换为十进制int res = Integer.parseInt(num, n);//System.out.println(res);//再转换为m进制String string = change(res, m);//输出if(string.length()>7){System.out.println("  ERROR");}else {System.out.printf("%7s",string);System.out.println();}}}public static String change(int n,int m){//十进制n的m进制char ch[] = {'0','1','2','3','4','5','6','7','8','9','A','B','C','D','E','F'};String string = "";while(n/m>0){string = ch[n%m]+string;n/=m;}if(n>0){//如果还有余数string = ch[n]+string;}return string;}}