C语言小游戏：三字棋（增强版本）

    上一篇博客发表了关于用C语言来实现小游戏三字棋的代码，但是这个代码中的电脑难度可谓是极低，我通过改变电脑落子的算法，增强了电脑的难度。具体思路为：一、让电脑优先判断自己是否有可能赢。二、判断自己可能赢的前提是，让自己能够知道自己在行、列、两条对角线中是否有两个相同的棋子，并且第三个地方为空，也就是‘ ’。三、如果电脑没有任何赢的可能，那么判断玩家在有行、列、两条对角线中是否有两个相同的棋子，并且第三个地方为空，进行对玩家的堵截。四、若电脑跟玩家都没有可能赢的情况那么让电脑自己随机产生一个坐标进行落子。以下为增强后的电脑下棋代码：

void RobotMove(char board[ROW][COL], int row, int col)//电脑走{    int i = 0;    int j = 0;    int a = 0;//a 用于限制一旦有一种判断成功，就不再进行其他判断    int b = 0;//b 用于对电脑即将赢的时候，不同判断产生后，进入不同的case    int c = 0;//c 用于对玩家即将赢的时候，不同判断产生后，进入不同的case    //电脑有两个连成线    if (a == 0)    {        for (i = 0; i < ROW; i++)//判断行        {            if ((board[i][0] == board[i][1] && board[i][0] == 'O'&&board[i][2] != 'X')                || (board[i][1] == board[i][2] && board[i][1] == 'O'&&board[i][0] != 'X')                || (board[i][0] == board[i][2] && board[i][0] == 'O'&&board[i][1] != 'X'))            {                a = 1;                b = 1;                break;            }        }    }    if (a == 0)    {        for (j = 0; j < ROW; j++)//判断列        {            if ((board[0][j] == board[1][j] && board[0][j] == 'O'&&board[2][j] != 'X')                || (board[1][j] == board[2][j] && board[1][j] == 'O'&&board[0][j] != 'X')                || (board[0][j] == board[2][j] && board[0][j] == 'O'&&board[1][j] != 'X'))            {                b = 2;                a = 1;                break;            }        }    }    if ((board[0][0] == board[1][1] && board[0][0] == 'O'&&board[2][2] != 'X')//第一条斜对角        || (board[1][1] == board[2][2] && board[1][1] == 'O'&&board[0][0] != 'X')        || (board[0][0] == board[2][2] && board[0][0] == 'O'&&board[1][1] != 'X')        && (a == 0))    {        b = 3;        a = 1;    }    if ((board[0][2] == board[1][1] && board[0][2] == 'O'&&board[2][0] != 'X')//第二条斜对角        || (board[1][1] == board[2][0] && board[1][1] == 'O'&&board[0][2] != 'X')        || (board[0][2] == board[2][0] && board[0][2] == 'O'&&board[1][1] != 'X')        && (a == 0))    {        b = 4;        a = 1;    }    switch (b)    {    case 1:        do        {            j = rand() % 3;//固定行不变，改变列，让棋子进入空白处            if (board[i][j] == ' ')            {                board[i][j] = 'O';                break;            }        } while (1);        break;    case 2:        do        {//rand()%3 产生0 1 2 之间的随机数            i = rand() % 3;//固定列不变，改变行，让棋子进入空白处            if (board[i][j] == ' ')            {                board[i][j] = 'O';                break;            }        } while (1);        break;    case 3:        do        {//第一条对角线            i = rand() % 3;            j = rand() % 3;            if ((i == j) && (board[i][j] == ' '))            {                board[i][j] = 'O';                break;            }        } while (1);        break;    case 4:        do        {//第二条对角线            i = rand() % 3;            j = rand() % 3;            if ((i == j) && (board[i][j] == ' ') && (i == 1) ||                (i == j + 2) && (board[i][j] == ' ') ||                (j == i + 2) && (board[i][j] == ' '))            {                board[i][j] = 'O';                break;            }        } while (1);        break;    }    //玩家有两个连起来的时候    if (a == 0)    {        for (i = 0; i < ROW; i++)        {            if ((board[i][0] == board[i][1] && board[i][0] == 'X'&&board[i][2] != 'O')                || (board[i][1] == board[i][2] && board[i][1] == 'X'&&board[i][0] != 'O')                || (board[i][0] == board[i][2] && board[i][0] == 'X'&&board[i][1] != 'O'))            {                c = 1;                a = 1;                break;            }        }    }    if (a == 0)    {        for (j = 0; j < ROW; j++)        {            if ((board[0][j] == board[1][j] && board[0][j] == 'X'&&board[2][j] != 'O')                || (board[1][j] == board[2][j] && board[1][j] == 'X'&&board[0][j] != 'O')                || (board[0][j] == board[2][j] && board[0][j] == 'X'&&board[1][j] != 'O'))            {                c = 2;                a = 1;                break;            }        }    }    if ((board[0][0] == board[1][1] && board[0][0] == 'X'&&board[2][2] != 'O')        || (board[1][1] == board[2][2] && board[1][1] == 'X'&&board[0][0] != 'O')        || (board[0][0] == board[2][2] && board[0][0] == 'X'&&board[1][1] != 'O')        && (a == 0))    {        c = 3;        a = 1;    }    if ((board[0][2] == board[1][1] && board[0][2] == 'X'&&board[2][0] != 'O')        || (board[1][1] == board[2][0] && board[1][1] == 'X'&&board[0][2] != 'O')        || (board[0][2] == board[2][0] && board[0][2] == 'X'&&board[1][1] != 'O')        && (a == 0))    {        c = 4;        a = 1;    }    switch (c)    {    case 1:        do        {            j = rand() % 3;            if (board[i][j] == ' ')            {                board[i][j] = 'O';                break;            }        } while (1);        break;    case 2:        do        {            i = rand() % 3;            if (board[i][j] == ' ')            {                board[i][j] = 'O';                break;            }        } while (1);        break;    case 3:        do        {            i = rand() % 3;            j = rand() % 3;            if ((i == j) && (board[i][j] == ' '))            {                board[i][j] = 'O';                break;            }        } while (1);        break;    case 4:        do        {            i = rand() % 3;            j = rand() % 3;            if ((i == j) && (board[i][j] == ' ') && (i == 1) ||                (i == j + 2) && (board[i][j] == ' ') ||                (j == i + 2) && (board[i][j] == ' '))            {                board[i][j] = 'O';                break;            }        } while (1);        break;    }    //若没有任何两个连线，则随机产生一个坐标    if (a == 0)    {        do        {            i = rand() % 3;            j = rand() % 3;            if (board[i][j] == ' ')            {                board[i][j] = 'O';                break;            }        } while (1);    }}

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